Lewis structure of HCN

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Lewis structure of HCN
Lewis structure of HCN | Image: Root Memory

The Lewis structure of HCN depicts the molecular arrangement of hydrogen cyanide, which comprises one hydrogen atom, one carbon atom, and one nitrogen atom. In this structure, carbon forms a single bond with hydrogen and a triple bond with nitrogen. The nitrogen atom has one lone pair of electrons, while both the hydrogen and carbon atoms have none. Hydrogen satisfies the duet rule, while both carbon and nitrogen fulfill the octet rule. There are no formal charges on any of the atoms, indicating a stable structure.

The accurate Lewis structure of HCN can be drawn in five simple steps. First, calculate the total number of valence electrons and select the central atom, which is the least electronegative among the atoms in HCN. Use this information to create a rough sketch of the molecule. Next, place electron pairs between the atoms in the sketch to represent the chemical bonds. Then, determine the total number of lone pairs and distribute them on the atoms, starting with the outer atoms and moving to the central atom to ensure proper distribution. After that, check whether each atom adheres to the octet rule, or the duet rule in the case of hydrogen. If any atom does not have a complete octet, adjust the lone pairs as needed. Finally, calculate the formal charge for each atom, indicate these charges on the atoms, and verify whether the structure is stable.

Steps

Draw skeleton

In this step, first calculate the total number of valence electrons. And then, decide the central atom.

  • Let’s calculate the total number of valence electrons

We know that… hydrogen is a group 1 element, carbon is a group 14 element, and nitrogen is a group 15 element. Hence, hydrogen has one valence electron, carbon has four valence electrons, and nitrogen has five valence electrons.

Now HCN has one hydrogen atom, one carbon atom, and one nitrogen atom.

So the total number of valence electrons = valence electrons of hydrogen atom + valence electrons of carbon atom + valence electrons of nitrogen atom

Therefore, the total number of valence electrons = 1 + 4 + 5 = 10

  • Now decide the central atom

We can not assume hydrogen as the central atom, because the central atom is bonded with at least two other atoms. And hydrogen has only one electron in its last shell, so it can not make more than one bond.

Therefore, choose the central atom from carbon and nitrogen.

The atom with the least electronegative value is placed at the center. By looking at the periodic table, we get the electronegativity values for carbon and nitrogen as follows:

Electronegativity value of carbon = 2.55
Electronegativity value of nitrogen = 3.04

Obviously, carbon is less electronegative than nitrogen. Hence, assume that carbon is the central atom.

So now, put carbon in the center and hydrogen and nitrogen on either side. And draw the rough skeleton structure for the Lewis structure of HCN something like this:

Skeleton structure for Lewis structure of HCN | Image: Root Memory

Show chemical bond

Place two electrons between the atoms to show a chemical bond. Since carbon is surrounded by hydrogen and nitrogen, use four electrons to show two chemical bonds as follows:

Two chemical bonds shown between atoms | Image: Root Memory

Mark lone pairs

As calculated earlier, we have a total of 10 valence electrons. And in the above structure, we have already used four valence electrons. Hence, six valence electrons are remaining.

Two valence electrons represent one lone pair. So six valence electrons = three lone pairs.

Note that hydrogen is a period 1 element, so it can not keep more than 2 electrons in its last shell. And both (carbon and nitrogen) are the period 2 elements, so they can not keep more than 8 electrons in their last shell.

Also, make sure that you start marking these lone pairs on outside atoms first. And then, on the central atom.

The outside atoms are hydrogen and nitrogen. But hydrogen can not keep more than 2 electrons in its last shell. Hence, don’t mark the lone pairs on hydrogen.

So nitrogen will get three lone pairs. And the central atom (carbon) will not get any lone pair, because all three lone pairs are used.

Now draw the Lewis structure of HCN something like this:

Lone pairs marked on Lewis structure of HCN | Image: Root Memory

In the above structure, you can see that the octet is completed on outside atoms. But, the central atom (carbon) doesn’t form an octet.

So in the next step, we have to complete the octet on the central atom.

Complete octet on central atom

Remember that carbon is a period 2 element, so it can not keep more than 8 electrons in its last shell.

Now carbon already has four valence electrons. Hence, carbon needs four more valence electrons to complete its octet.

So convert two lone pairs from the nitrogen atom to make a new bond with the carbon atom. And then, the Lewis structure of HCN looks something like this:

Lone pair of nitrogen is converted, and octet/duet is completed on atoms | Image: Root Memory

In the above structure, you can see that the octet is completed on the central atom (carbon), and also on the outside atoms. Therefore, the octet rule is satisfied.

After completing the octet, one last thing we need to do is, calculate the formal charge and check the stability of the above structure.

Calculate formal charge and check stability

The following formula is used to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

Collect the data from the above structure and then, write it down below as follows:

  • For hydrogen atom

Valence electrons = 1
Nonbonding electrons = 0
Bonding electrons = 2

Formal charge = 1 – 0 – ½ (2) = 0

  • For carbon atom

Valence electrons = 4
Nonbonding electrons = 0
Bonding electrons = 8

Formal charge = 4 – 0 – ½ (8) = 0

  • For nitrogen atom

Valence electrons = 5
Nonbonding electrons = 2
Bonding electrons = 6

Formal charge = 5 – 2 – ½ (6) = 0

Mention the formal charges of atoms on the structure. So the Lewis structure of HCN looks something like this:

Formal charges are calculated, and got the stable Lewis structure of HCN | Image: Root Memory

In the above structure, you can see that the formal charges of all atoms are zero. Therefore, this is the stable Lewis structure of HCN.

And each horizontal line drawn in the above structure represents a pair of bonding valence electrons.

Next: Lewis structure of SO2

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Deep

Rootmemory.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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