Lewis structure of P4

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Lewis structure of P4
Lewis structure of P4

The Lewis structure of P4 contains six single bonds, with one phosphorus in the center, and three other phosphorus on either side. And there is one lone pair on each phosphorus atom.

Steps

By using the following steps, you can easily draw the Lewis structure of P4.

#1 Draw skeleton
#2 Show chemical bond
#3 Mark lone pairs
#4 Calculate formal charge and check stability (if octet is already completed on central atom)

Let’s one by one discuss each step in detail.

#1 Draw skeleton

In this step, first calculate the total number of valence electrons. And then, decide the central atom.

  • Let’s calculate the total number of valence electrons

We know that… phosphorus is a group 15 element. Hence, phosphorus has five valence electrons.

Now P4 has four phosphorus atoms.

So the total number of valence electrons = valence electrons of phosphorus atom × 4

Therefore, the total number of valence electrons = 5 × 4 = 20

  • Now decide the central atom

There are four phosphorus atoms in P4. Hence, we can assume any one as the central atom. Let’s assume that center phosphorus is the central atom.

So now, put one phosphorus in the center and three other phosphorus on either side. And draw the rough skeleton structure for the Lewis structure of P4 something like this:

Skeleton structure for Lewis structure of P4

#2 Show chemical bond

Place two electrons between the atoms to show a chemical bond. Since center phosphorus is surrounded by three other phosphorus, use twelve electrons to show six chemical bonds as follows:

Six chemical bonds shown between atoms

#3 Mark lone pairs

As calculated earlier, we have a total of 20 valence electrons. And in the above structure, we have already used twelve valence electrons. Hence, eight valence electrons are remaining.

Two valence electrons represent one lone pair. So eight valence electrons = four lone pairs.

Note that phosphorus is a period 3 element, so it can keep more than 8 electrons in its last shell.

Also, make sure that you start marking these lone pairs on outside atoms first. And then, on the central atom.

The outside atoms are top phosphorus and bottom phosphorus, so top phosphorus and bottom phosphorus will get one lone pair. And the central atom (center phosphorus) will also get one lone pair.

So the Lewis structure of P4 looks something like this:

Lone pairs marked on Lewis structure of P4

In the above structure, you can see that the octet is completed on the central atom (center phosphorus), and also on the outside atoms. Therefore, the octet rule is satisfied.

After completing the octet, one last thing we need to do is, calculate the formal charge and check the stability of the above structure.

#4 Calculate formal charge and check stability

The following formula is used to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

Collect the data from the above structure and then, write it down below as follows:

  • For each phosphorus atom

Valence electrons = 5
Nonbonding electrons = 2
Bonding electrons = 6

Formal charge = 5 – 2 – ½ (6) = 0

Mention the formal charges of atoms on the structure. So the Lewis structure of P4 looks something like this:

Formal charges are calculated, and got the stable Lewis structure of P4

In the above structure, you can see that the formal charges of all phosphorus are zero. Therefore, this is the stable Lewis structure of P4.

And each horizontal line drawn in the above structure represents a pair of bonding valence electrons.

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Deep

Rootmemory.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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