Lewis structure of BrCl

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Lewis structure of BrCl
Lewis structure of BrCl | Image: Root Memory

The Lewis structure of BrCl contains a single bond between the bromine atom and chlorine atom, and both the atoms have three lone pairs.

Steps

By using the following steps, you can easily draw the Lewis structure of BrCl.

#1 Draw skeleton
#2 Show chemical bond
#3 Mark lone pairs
#4 Calculate formal charge and check stability (if octet is already completed on central atom)

Let’s one by one discuss each step in detail.

#1 Draw skeleton

In this step, first calculate the total number of valence electrons. And then, decide the central atom.

  • Let’s calculate the total number of valence electrons

We know that… both bromine and chlorine are the group 17 elements. Hence, both bromine and chlorine have seven valence electrons.

Now BrCl has one bromine atom and one chlorine atom.

So the total number of valence electrons = valence electrons of bromine atom + valence electrons of chlorine atom

Therefore, the total number of valence electrons = 7 + 7 = 14

  • Now decide the central atom

The atom with the least electronegative value is placed at the center. By looking at the periodic table, we get the electronegativity values for bromine and chlorine as follows:

Electronegativity value of bromine = 2.96
Electronegativity value of chlorine = 3.16

Obviously, bromine is less electronegative than chlorine. Hence, assume that bromine is the central atom.

So now, put bromine and chlorine next to each other. And draw the rough skeleton structure for the Lewis structure of BrCl something like this:

Skeleton structure for Lewis structure of BrCl | Image: Root Memory

#2 Show chemical bond

Place two electrons between the atoms to show a chemical bond as follows:

One chemical bond shown between atoms | Image: Root Memory

#3 Mark lone pairs

As calculated earlier, we have a total of 14 valence electrons. And in the above structure, we have already used two valence electrons. Hence, twelve valence electrons are remaining.

Two valence electrons represent one lone pair. So twelve valence electrons = six lone pairs.

Note that bromine is a period 4 element, so it can keep more than 8 electrons in its last shell. And chlorine is a period 3 element, so it can keep more than 8 electrons in its last shell.

Also, make sure that you start marking these lone pairs on outside atoms first. And then, on the central atom.

The outside atom is chlorine, so chlorine will get three lone pairs. And the central atom (bromine) will also get three lone pairs.

So the Lewis structure of BrCl looks something like this:

Lone pairs marked on Lewis structure of BrCl | Image: Root Memory

In the above structure, you can see that the octet is completed on the central atom (bromine), and also on the outside atom. Therefore, the octet rule is satisfied.

After completing the octet, one last thing we need to do is, calculate the formal charge and check the stability of the above structure.

#4 Calculate formal charge and check stability

The following formula is used to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

Collect the data from the above structure and then, write it down below as follows:

  • For bromine atom

Valence electrons = 7
Nonbonding electrons = 6
Bonding electrons = 2

Formal charge = 7 – 6 – ½ (2) = 0

  • For chlorine atom

Valence electrons = 7
Nonbonding electrons = 6
Bonding electrons = 2

Formal charge = 7 – 6 – ½ (2) = 0

Mention the formal charges of atoms on the structure. So the Lewis structure of BrCl looks something like this:

Formal charges are calculated, and got the stable Lewis structure of BrCl | Image: Root Memory

In the above structure, you can see that the formal charges of both (bromine and chlorine) are zero. Therefore, this is the stable Lewis structure of BrCl.

And the horizontal line drawn in the above structure represents a pair of bonding valence electrons.

Related

External links

Deep

Rootmemory.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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