Lewis structure of C4H10

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Lewis structure of C4H10
Lewis structure of C4H10

The Lewis structure of C4H10 contains thirteen single bonds, with four carbons in the center. The left carbon and right carbon are attached with three hydrogens, and two center carbons are attached with two hydrogens. Both hydrogen atom and carbon atom do not have any lone pair.

Steps

By using the following steps, you can easily draw the Lewis structure of C4H10.

#1 Draw skeleton
#2 Show chemical bond
#3 Calculate formal charge and check stability (if there are no lone pairs and octet is already completed on central atom)

Let’s one by one discuss each step in detail.

#1 Draw skeleton

In this step, first calculate the total number of valence electrons. And then, decide the central atom.

  • Let’s calculate the total number of valence electrons

We know that… carbon is a group 14 element and hydrogen is a group 1 element. Hence, carbon has four valence electrons and hydrogen has one valence electron.

Now C4H10 has four carbon atoms and ten hydrogen atoms.

So the total number of valence electrons = (valence electrons of carbon atom × 4) + (valence electrons of hydrogen atom × 10)

Therefore, the total number of valence electrons = 16 + 10 = 26

  • Now decide the central atom

We can not assume hydrogen as the central atom, because the central atom is bonded with at least two other atoms. And hydrogen has only one electron in its last shell, so it can not make more than one bond.

Therefore, choose carbon as the central atom.

But there are four carbon atoms in C4H10. Hence, we can assume any one as the central atom. Let’s assume that left carbon is the central atom.

So now, put four carbons in the center and ten hydrogens on either side. And draw the rough skeleton structure for the Lewis structure of C4H10 something like this:

Skeleton structure for Lewis structure of C4H10

#2 Show chemical bond

Place two electrons between the atoms to show a chemical bond. Since four carbons are surrounded by ten hydrogens, use twenty-six electrons to show thirteen chemical bonds as follows:

Thirteen chemical bonds shown between atoms

In the above structure, you can see that the octet is completed on the central atom (left carbon), and also on the outside atoms. Therefore, the octet rule is satisfied.

After completing the octet, one last thing we need to do is, calculate the formal charge and check the stability of the above structure.

#3 Calculate formal charge and check stability

The following formula is used to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

Collect the data from the above structure and then, write it down below as follows:

  • For each carbon atom

Valence electrons = 4
Nonbonding electrons = 0
Bonding electrons = 8

Formal charge = 4 – 0 – ½ (8) = 0

  • For each hydrogen atom

Valence electrons = 1
Nonbonding electrons = 0
Bonding electrons = 2

Formal charge = 1 – 0 – ½ (2) = 0

Mention the formal charges of atoms on the structure. So the Lewis structure of C4H10 looks something like this:

Formal charges are calculated, and got the stable Lewis structure of C4H10

In the above structure, you can see that the formal charges of both (carbon and hydrogen) are zero. Therefore, this is the stable Lewis structure of C4H10.

And each horizontal line drawn in the above structure represents a pair of bonding valence electrons.

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Deep

Rootmemory.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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