The Lewis structure of CSe2 contains two double bonds, with carbon in the center, and two seleniums on either side. There are two lone pairs on each selenium atom, and the carbon atom does not have any lone pair.
Steps
By using the following steps, you can easily draw the Lewis structure of CSe2.
#1 Draw skeleton
#2 Show chemical bond
#3 Mark lone pairs
#4 Complete octet on central atom
#5 Calculate formal charge and check stability
Let’s one by one discuss each step in detail.
#1 Draw skeleton
In this step, first calculate the total number of valence electrons. And then, decide the central atom.
- Let’s calculate the total number of valence electrons
We know that… carbon is a group 14 element and selenium is a group 16 element. Hence, carbon has four valence electrons and selenium has six valence electrons.
Now CSe2 has one carbon atom and two selenium atoms.
So the total number of valence electrons = valence electrons of carbon atom + (valence electrons of selenium atom × 2)
Therefore, the total number of valence electrons = 4 + 12 = 16
- Now decide the central atom
The atom with the least electronegative value is placed at the center. By looking at the periodic table, we get the electronegativity values for carbon and selenium as follows:
Electronegativity value of carbon = 2.55
Electronegativity value of selenium = 2.55
Here, carbon and selenium have the same electronegativity values. But if we assume selenium as the central atom, then we do not get the formal charges on atoms closer to zero.
Hence, assume that carbon is the central atom.
So now, put carbon in the center and seleniums on either side. And draw the rough skeleton structure for the Lewis structure of CSe2 something like this:
Also read: How to draw Lewis structure of BeBr2 (4 steps)
#2 Show chemical bond
Place two electrons between the atoms to show a chemical bond. Since carbon is surrounded by two seleniums, use four electrons to show two chemical bonds as follows:
#3 Mark lone pairs
As calculated earlier, we have a total of 16 valence electrons. And in the above structure, we have already used four valence electrons. Hence, twelve valence electrons are remaining.
Two valence electrons represent one lone pair. So twelve valence electrons = six lone pairs.
Note that carbon is a period 2 element, so it can not keep more than 8 electrons in its last shell. And selenium is a period 4 element, so it can keep more than 8 electrons in its last shell.
Also, make sure that you start marking these lone pairs on outside atoms first. And then, on the central atom.
The outside atoms are seleniums, so each selenium will get three lone pairs. And the central atom (carbon) will not get any lone pair, because all six lone pairs are used.
So the Lewis structure of CSe2 looks something like this:
In the above structure, you can see that the octet is completed on outside atoms. But, the central atom (carbon) doesn’t form an octet.
So in the next step, we have to complete the octet on the central atom.
Also read: How to draw Lewis structure of XeO2F2 (5 steps)
#4 Complete octet on central atom
Remember that carbon is a period 2 element, so it can not keep more than 8 electrons in its last shell.
Now carbon already has four valence electrons. Hence, carbon needs four more valence electrons to complete its octet.
So convert one lone pair from each selenium atom to make a new bond with the carbon atom. And then, the Lewis structure of CSe2 looks something like this:
In the above structure, you can see that the octet is completed on the central atom (carbon), and also on the outside atoms. Therefore, the octet rule is satisfied.
After completing the octet, one last thing we need to do is, calculate the formal charge and check the stability of the above structure.
Also read: How to draw Lewis structure of AlBr3 (4 steps)
#5 Calculate formal charge and check stability
The following formula is used to calculate the formal charges on atoms:
Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons
Collect the data from the above structure and then, write it down below as follows:
- For carbon atom
Valence electrons = 4
Nonbonding electrons = 0
Bonding electrons = 8
Formal charge = 4 – 0 – ½ (8) = 0
- For each selenium atom
Valence electrons = 6
Nonbonding electrons = 4
Bonding electrons = 4
Formal charge = 6 – 4 – ½ (4) = 0
Mention the formal charges of atoms on the structure. So the Lewis structure of CSe2 looks something like this:
In the above structure, you can see that the formal charges of both (carbon and selenium) are zero. Therefore, this is the stable Lewis structure of CSe2.
And each horizontal line drawn in the above structure represents a pair of bonding valence electrons.
Related
- Lewis structure of BeBr2
- Lewis structure of XeO2F2
- Lewis structure of AlBr3
- Lewis structure of N2O5
- Lewis structure of CHBr3
External links
- CSe2 Lewis Structure in 6 Steps (With Images) – Pediabay
- CSe2 Lewis Structure, Geometry, Hybridization, and Polarity – Techiescientist
- Carbon Diselenide, CSe2 Molecular Geometry & Polarity – Tutor-Homework.com
- Draw the Lewis structure for CSe2 – Chegg
- Draw the Lewis structure for CSe2 – Brainly
- Write electron-dot formulas for the following: SeOCl2, CSe2 – Homework.Study.com
- Draw the Lewis Structure of CSe2 – Bartleby
- CSe2 (Carbon Diselenide) Oxidation Number – ChemicalAid
Deep
Rootmemory.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.