Lewis structure of XeCl2

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Lewis structure of XeCl2
Lewis structure of XeCl2 | Image: Root Memory

The Lewis structure of XeCl2 contains two single bonds, with xenon in the center, and two chlorines on either side. There are three lone pairs on both the chlorine atom and xenon atom.

Steps

By using the following steps, you can easily draw the Lewis structure of XeCl2.

#1 Draw skeleton
#2 Show chemical bond
#3 Mark lone pairs
#4 Calculate formal charge and check stability (if octet is already completed on central atom)

Let’s one by one discuss each step in detail.

#1 Draw skeleton

In this step, first calculate the total number of valence electrons. And then, decide the central atom.

  • Let’s calculate the total number of valence electrons

We know that… xenon is a group 18 element and chlorine is a group 17 element. Hence, xenon has eight valence electrons and chlorine has seven valence electrons.

Now XeCl2 has one xenon atom and two chlorine atoms.

So the total number of valence electrons = valence electrons of xenon atom + (valence electrons of chlorine atom × 2)

Therefore, the total number of valence electrons = 8 + 14 = 22

  • Now decide the central atom

The atom with the least electronegative value is placed at the center. By looking at the periodic table, we get the electronegativity values for xenon and chlorine as follows:

Electronegativity value of xenon = 2.6
Electronegativity value of chlorine = 3.16

Obviously, xenon is less electronegative than chlorine. Hence, assume that xenon is the central atom.

So now, put xenon in the center and chlorines on either side. And draw the rough skeleton structure for the Lewis structure of XeCl2 something like this:

Skeleton structure for Lewis structure of XeCl2 | Image: Root Memory

#2 Show chemical bond

Place two electrons between the atoms to show a chemical bond. Since xenon is surrounded by two chlorines, use four electrons to show two chemical bonds as follows:

Two chemical bonds shown between atoms | Image: Root Memory

#3 Mark lone pairs

As calculated earlier, we have a total of 22 valence electrons. And in the above structure, we have already used four valence electrons. Hence, eighteen valence electrons are remaining.

Two valence electrons represent one lone pair. So eighteen valence electrons = nine lone pairs.

Note that xenon is a period 5 element, so it can keep more than 8 electrons in its last shell. And chlorine is a period 3 element, so it can keep more than 8 electrons in its last shell.

Also, make sure that you start marking these lone pairs on outside atoms first. And then, on the central atom.

The outside atoms are chlorines, so each chlorine will get three lone pairs. And the central atom (xenon) will also get three lone pairs.

So the Lewis structure of XeCl2 looks something like this:

Lone pairs marked on Lewis structure of XeCl2 | Image: Root Memory

In the above structure, you can see that the octet is completed on the central atom (xenon), and also on the outside atoms. Therefore, the octet rule is satisfied.

After completing the octet, one last thing we need to do is, calculate the formal charge and check the stability of the above structure.

#4 Calculate formal charge and check stability

The following formula is used to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

Collect the data from the above structure and then, write it down below as follows:

  • For xenon atom

Valence electrons = 8
Nonbonding electrons = 6
Bonding electrons = 4

Formal charge = 8 – 6 – ½ (4) = 0

  • For each chlorine atom

Valence electrons = 7
Nonbonding electrons = 6
Bonding electrons = 2

Formal charge = 7 – 6 – ½ (2) = 0

Mention the formal charges of atoms on the structure. So the Lewis structure of XeCl2 looks something like this:

Formal charges are calculated, and got the stable Lewis structure of XeCl2 | Image: Root Memory

In the above structure, you can see that the formal charges of both (xenon and chlorine) are zero. Therefore, this is the stable Lewis structure of XeCl2.

And each horizontal line drawn in the above structure represents a pair of bonding valence electrons.

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External links

Deep

Rootmemory.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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